jquery - Get only common objects from a list of arrays in javascript -

i have couple arrays in javascript code (i'm using knockout js too) , want single array contains common objects of arrays.

my code this:

array1 = [{a: 1, b: 'something'}, {a: 2, b: 'something1'},{a: 3, b: 'something3'}];  array2 = [{a: 3, b: 'something3'}, {a: 1, b: 'something'}, {a: 4, b: 'something4'}]  array2 = [{a: 3, b: 'something3'}, {a: 1, b: 'something'}, {a: 5, b: 'something5'}] 

so, arrays want common of 1 single array, result this:

array4 = [{a: 1, b: 'something'}, {a: 3, b: 'something3'}] 

i have mention array1, array2 , array3 inside array this:

array0 = [array1, array2, array3]; 

i hope can me this, thank you!

for example:

array1 = [{a: 1, b: 'something'}, {a: 2, b: 'something1'},{a: 3, b: 'something3'}]; array2 = [{a: 3, b: 'something3'}, {a: 1, b: 'something'}, {a: 4, b: 'something4'}] array3 = [{a: 3, b: 'something3'}, {a: 1, b: 'something'}, {a: 5, b: 'something5'}]  = [array1, array2, array3]  objects = {} counter = {}  all.map(function(ary, n) {     ary.map(function(obj) {         var key = json.stringify(obj);         objects[key] = obj;         counter[key] = (counter[key] || 0) | (1 << n);     }) })  intersection = [] object.keys(counter).map(function(key) {     if(counter[key] == (1 << all.length) - 1)         intersection.push(objects[key]); })  console.log(intersection) 

the idea put objects in hash table using json representations keys.