vb.net For loop in If statement - shorten the ElseIf -

how shorten this: information: %washv% constant coming outer loop %loop%.

i tried loop in elseif / new if statement failed

thanks.

code:

|if [%loop%] = "1" return "true"  elseif [%loop%] =96-(96-round([5000/%washv%])) return "true"  elseif [%loop%] =96-(96-2*round([5000/%washv%])) return "true"  elseif [%loop%] =96-(96-3*round([5000/%washv%])) return "true" elseif [%loop%] =96-(96-4*round([5000/%washv%])) return "true"  elseif [%loop%] =96-(96-5*round([5000/%washv%])) return "true"  elseif [%loop%] =96-(96-6*round([5000/%washv%])) return "true"  elseif [%loop%] =96-(96-7*round([5000/%washv%])) return "true"  elseif [%loop%] =96-(96-8*round([5000/%washv%])) return "true"  elseif [%loop%] =96-(96-9*round([5000/%washv%])) return "true"  else  return "false“  end if| 

if vb.net, simplification can done this:

for integer = 1 9     if [%loop%] =96-(96-i*round([5000/%washv%]))         return "true"     end if next  return if([%loop%] = "1", "true", "false") 

yet, more pressing matter find out use of %loop% , %washv%.

the use of % in rightside of vb.net variable during initialization indicates integer:

dim a% 'integer 

check this: what percentage symbol mean part of variable name?

there many other symbols $, &, !, @, , # too.

but left %, know not.

it looks more query language me, this:

... s '%loop%'