c - How to convert binary int array to hex char array? -

say have 32 bit long array of 32 binary digits , want output in hex form. how that? have right long , don't know how compare 4 binary digits corresponding hex number

this have right break 32 bit number 4 bit binary , try find matching number in binarydigits

char hexchars[16] ={'0','1','2','3','4','5','6','7','8','9','a','b','c','d','e','f'}; char * binarydigits[16] = {"0000","0001","0010","0011","0100","0101","0110","0111","1000","1001","1010","1011","1100","1101","1110","1111"};  int binarynum[32]= {'0','0','1','0','0','0','0','1','0','0','0','0','1','0','0','1','0','0','0','0','0','0','0','0','0','0','0','0','1','0','1','0'}; int currentblock, hexdigit; int a=0, b=1, i=0; while (a<32) {     for(a=i+3;a>=i;a--)     {         current=binarynum[a];         temp=current*b;         currentblock=currentblock+temp;         b*=10;     }     i=a;      while(match==0)     {         if(currentblock != binarydigits[y])             y++;         else         {             match=1;             hexdigit=binarydigits[y];             y=0;             printf("%d",hexdigit);         }     } }  printf("\n%d",currentblock); 

i apologize if isn't crux of issue, say

i have 32 bit long array of 32 binary digits

however, int binarynum[32] 32-integer long array (4 bytes per int, 8 bits per byte = 4 * 8 * 32 (1024 bits)). making things unclear.

further, assigning ascii character values '0' (which 0x30 hex or 48 decimal) , '1' (0x31, 49) each location in binarynum. can it, , gymnastics compare each value form

32 bit long array of 32 binary digits

but if have, why not write way? (as binary constant). give 32-bit binary value. example:

#include <stdio.h>  int main (void) {      unsigned binarynum = 0b00100001000010010000000000001010;      printf ("\n binarynum : 0x%8x  (%u decimal)\n\n", binarynum, binarynum);      return 0; } 

output

$ ./bin/binum32   binarynum : 0x2109000a  (554237962 decimal) 

if not difficulty lies, please explain further, or again, trying accomplish.