Python: function that gets n-th element of a list -

i have list of strings

['abc', 'def', 'ghij']

and want list of strings containing first letter of each string, i.e.

['a', 'd', 'g'].

i thought doing using map , function returns first element of list: my_list[0]. how can pass map?

thanks.

you should use list comprehension, @avasal since it's more pythonic, here's how map:

>>> operator import itemgetter    >>> l = ['abc', 'def', 'ghij']  >>> map(itemgetter(0), l) ['a', 'd', 'g']

Scrio